Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 363: 132

Answer

$(x^n+1)(9x^{n}-8)$.

Work Step by Step

The given expression is $=9x^{2n}+x^n-8$ Rewrite the term $x^n$ as $9x^n-8x^n$. $=9x^{2n}+9x^n-8x^n-8$ Group terms. $=9x^{n}(x^n+1)-8(x^n+1)$ Factor out $(x^n+1)$ $=(x^n+1)(9x^{n}-8)$.
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