Answer
(a.) Slope-intercept form $y=\frac{-5}{3}x+5$.
(b.) Slope $m=\frac{-5}{3}$ and $y−$ intercept is $b=5$.
(c.) The graph is shown below.
Work Step by Step
(a) The standard slope-intercept form is $y=mx+c$.
Where, $m=$ slope and $c=y−$intercept.
The given equation is $5x+3y=15$.
Isolate $y$.
$y=\frac{-5}{3}x+5$.
(b.) The slope of the equation is $m=\frac{-5}{3}$.
and the $y−$ intercept is $b=5$.
(c.) The first point is $(0,5)$, because $b=5$.
For the second point use slope.
slope $=\frac{-5}{3}=\frac{Rise}{Run}$.
The second point is $(0+3,5-5)=(3,0)$.
By using these two point draw a straight line.
