Answer
(a.) Slope-intercept form $ y=\frac{4}{5}x $.
(b.) Slope $ m= \frac{4}{5}$ and $ y- $ intercept is $ b=0 $.
(c.) The graph is attached.
Work Step by Step
(a) The standard slope-intercept form is $ y=mx+c $.
Where, $ m= $ slope and $ c= y-$intercept.
The given equation is $ 5y=4x $.
Isolate $ y $.
$ y=\frac{4}{5}x $
(b.) The slope of the equation is $ m=\frac{4}{5} $
and the $ y- $intercept is $ b=0 $.
(c.) The first point is $ (0,0) $, because $ b=0 $.
For the second point use slope.
slope $ \frac{4}{5} = \frac {Rise}{Run}$.
The second point is $ (0+5,0+4) = (5,4) $.
By using these two point draw a straight line.
