Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.4 - Linear Functions and Slope - Exercise Set - Page 152: 28

Answer

$\begin{array}{l|l} line & slope\\ \hline L_{1} & 1\\ L_{2} & 2/3\\ L_{3} & -2 \end{array}$

Work Step by Step

Slope is defined as $m=\displaystyle \frac{\text{change in y}}{\text{change in x}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} .$ Line $L_{1}$ passes through $(-1,-2)$ and $(1,0)$ $m_{1}=\displaystyle \frac{0-(-2)}{1-(-1)}=\frac{2}{2}=1$ Line $L_{2}$ passes through $(1,-4)$ and $(4,-2)$ $m_{2}=\displaystyle \frac{-2-(-4)}{4-1}=\frac{2}{3}$ Line $L_{3}$ passes through $(-4,2)$ and $(-3,0)$ $m_{3}=\displaystyle \frac{0-2}{-3-(-4)}=\frac{-2}{1}=-2$
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