Answer
(a.) Slope-intercept form $y=\frac{3}{4}x$.
(b.) Slope $m=\frac{3}{4}$ and $y−$ intercept is $b=0$.
(c.) The graph is shown below.
Work Step by Step
(a) The standard slope-intercept form is $y=mx+c$.
Where, $m=$ slope and $c=y−$intercept.
The given equation is $4y=3x$.
Isolate $y$.
$y=\frac{3}{4}x$.
(b.) The slope of the equation is $m=\frac{3}{4}$.
and the $y−$ intercept is $b=0$.
(c.) The first point is $(0,0)$, because $b=0$.
For the second point use slope.
slope $=\frac{3}{4}=\frac{Rise}{Run}$.
The second point is $(0+4,0+3)=(4,3)$.
By using these two point draw a straight line.
