Chapter 9 - Section 9.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 586: 93

Please see the graph.

$f(x)= log (x+2)$ $x=8$ $f(x)= log {x+2}$ $f(8)= log {8+2}$ $f(8)= log 10$ $f(8)= 1$ $x=-1$ $f(x)= log {x+2}$ $f(-1)= log {-1+2}$ $f(-1)= log 1$ $f(-1)=0$ $x=98$ $f(x)= log {x+2}$ $f(98) =log {98+2}$ $f(98)= log 100$ $f(98)= log 10^2$ $f(98)= 2$ $(-1,0)$, $(8, 1)$, and $(98,2)$ are on the curve.