Chapter 9 - Section 9.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 586: 82

Please see the graph.

$f(x)=e^{-x}$ $x=-1$ $f(x)=e^{-x}$ $f(-1)=e^{-1*-1}$ $f(-1)=e$ $x=-2$ $f(x)=e^{-x}$ $f(-2)=e^{-2*-1}$ $f(-2)=e^2$ $x=0$ $f(x)=e^{-x}$ $f(0)=e^0$ $f(0)=1$ $(0,1)$, $(-1,e)$, and $(-2,e^2)$ are on the curve.