Chapter 9 - Section 9.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 586: 85

Please see the graph.

$f(x)=e^{x-1}$ $x=1$ $f(x)=e^{x-1}$ $f(1)=e^{1-1}$ $f(1)=e^0$ $f(1)=1$ $x=2$ $f(x)=e^{x-1}$ $f(2)=e^{2-1}$ $f(2)=e^1$ $f(2)=e$ $x=0$ $f(x)=e^{x-1}$ $f(0)=e^{0-1}$ $f(0)={-1}$ $f(0)=1/e$ $(0,1/e)$, $(1,1)$, and $(2,e)$ are on the curve.