Answer
$x+2x^{.5}-15$
Work Step by Step
$(x^{1/2}-3)(x^{1/2}+5)$
$w=x^{1/2}$
$(w-3)(w+5)$
$w*w+w*5+(-3)*w+(-3)*5$
$w^2+5w-3w-15$
$w^2+2w-15$
$w=x^{1/2}$
$w^2+2w-15$
$(x^{.5})^2+2(x^{.5})-15$
$x^1+2x^{.5}-15$
$x+2x^{.5}-15$
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