Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 601: 26b

Answer

$x+2x^{.5}-15$

Work Step by Step

$(x^{1/2}-3)(x^{1/2}+5)$ $w=x^{1/2}$ $(w-3)(w+5)$ $w*w+w*5+(-3)*w+(-3)*5$ $w^2+5w-3w-15$ $w^2+2w-15$ $w=x^{1/2}$ $w^2+2w-15$ $(x^{.5})^2+2(x^{.5})-15$ $x^1+2x^{.5}-15$ $x+2x^{.5}-15$
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