Answer
$9$
Work Step by Step
RECALL:
$\dfrac{\frac{a}{b}}{\frac{c}{d}}=\dfrac{a}{b} \cdot \dfrac{d}{c}$
Use the rule above to have:
$\\=\dfrac{15}{2x} \cdot \dfrac{6x}{5}$
Cancel the common factors to have:
$\require{cancel}
\\=\dfrac{\cancel{15}3}{\cancel{2x}} \cdot \dfrac{\cancel{6x}3}{\cancel{5}}
\\=9$
