Answer
The error is that the parenthesis is lacking before the expression $x-6$;
$\dfrac{x+3}{x^2+1}$
Work Step by Step
The error is that the parenthesis is lacking before the expression $x-6$. The correct solution is
\begin{array}{l}\require{cancel}
\dfrac{2x-3-(x-6)}{x^2+1}
\\\\=
\dfrac{2x-3-x+6}{x^2+1}
\\\\=
\dfrac{x+3}{x^2+1}
.\end{array}