Answer
see graph
Work Step by Step
Let
\begin{array}{l}\require{cancel}Y_1=
4x^{-2}-3x^{-1}
,\text{ and }\\Y_2=
\dfrac{4-3x}{x^2}
,\end{array}
where $Y_1$ is the given in item $107$ and $Y_2$ is the answer to item $107.$ Using a graphing calculator, the red dotted graph is the graph of $Y_1$ and the blue solid graph is the graph of $Y_2.$ Since the graphs coincide, then $Y_1$ and $Y_2$ are equal. That is, $Y_2$ is the simplified form of $Y_1.$
