Answer
$(x+9)(x+3)$
Work Step by Step
Let $z=
(x+4)
$. Then,
\begin{align*}
2(x+4)^2+3(x+4)-5
\Rightarrow
2z^2+3z-5
\\=
(2z+5)(z-1)
\\=
[(x+4)+5][(x+4)-1]
\text{since $z=(x+4)$}
\\=
(x+9)(x+3)
.\end{align*}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 303: 63
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