Answer
$2(3x-5)(2x+5)$
Work Step by Step
Factoring the $GCF=2$ of the given expression, $
12x^2+10x-50
$, results to
\begin{array}{l}\require{cancel}
2(6x^2+5x-25)
.\end{array}
The two numbers whose product is $ac=
6(-25)=-150
$ and whose sum is $b=
5
$ are $\{
-10,15
\}$. Using these two numbers to decompose the middle term, then the factored form of the resulting expression, $
2(6x^2+5x-25)
$,is
\begin{array}{l}\require{cancel}
2(6x^2-10x+15x-25)
\\\\=
2[(6x^2-10x)+(15x-25)]
\\\\=
2[2x(3x-5)+5(3x-5)]
\\\\=
2[(3x-5)(2x+5)]
\\\\=
2(3x-5)(2x+5)
.\end{array}
