Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.6 - Factoring Trinomials - Exercise Set - Page 303: 58

Answer

$(x+5)(x-1)$

Work Step by Step

The two numbers whose product is $ac= 1(-5)=-5 $ and whose sum is $b= 4 $ are $\{ 5,-1 \}$. Using these two numbers to decompose the middle term, then the factored form of the expression, $ x^2+4x-5 $, is \begin{array}{l}\require{cancel} x^2+5x-x-5 \\\\= (x^2+5x)-(x+5) \\\\= x(x+5)-(x+5) \\\\= (x+5)(x-1) .\end{array}
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