Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 295: 73

Answer

125$x^{6}$

Work Step by Step

1. Take the numeral to the 3rd power: $5^{3}$ = 125 2. Take the variable to the 3rd power by multiplying the exponents. 2 x 3 = 6, so $($x^{2}$)^{3}$ = $x^{6}$ 3. Put the two together: 125$x^{6}$
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