Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 295: 48

Answer

2a (2a$b^{2}$c - 3$b^{2}$c - 2c + 4)

Work Step by Step

We are given the polynomial 4$a^{2}$$b^{2}$c - 6a$b^{2}$c - 4ac + 8a. The GCF of all terms is 2a, so we can factor that out from each term. 2a(2a$b^{2}$c) + 2a(-3$b^{2}$c) + 2a(-2c) + 2a(4) Next, we can use the distributive property. 2a (2a$b^{2}$c - 3$b^{2}$c - 2c + 4)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.