Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 295: 15

Answer

$4ab(2a^2b^2-ab+1+4b)$

Work Step by Step

Factoring the $GCF= 4ab $, then, \begin{align*} 8a^3b^3-4a^2b^2+4ab+16ab^2 \Rightarrow 4ab(2a^2b^2-ab+1+4b) .\end{align*}
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