Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.3 - Polynomials and Polynomial Functions - Exercise Set - Page 279: 23

Answer

$-\frac{11}{16}$

Work Step by Step

We can find the value of $Q(\frac{1}{4})$ by plugging $\frac{1}{4}$ into the formula for $Q(x)$. $Q(x)=5x^{2}-1$ $Q(\frac{1}{4})=5(\frac{1}{4})^{2}-1=5\times(\frac{1}{4}\times\frac{1}{4})-1=5\times\frac{1}{16}-1=\frac{5}{16}-\frac{16}{16}=-\frac{11}{16}$
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