Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.3 - Polynomials and Polynomial Functions - Exercise Set - Page 279: 22

Answer

13

Work Step by Step

We can find the value of $P(-4)$ by plugging -4 into the formula for $P(x)$. $P(x)=x^{2}+x+1$ $P(-4)=(-4)^{2}+(-4)+1=(-4\times-4)-4+1=16-4+1=13$
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