Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.3 - Polynomials and Polynomial Functions - Exercise Set - Page 279: 21

Answer

499

Work Step by Step

We can find the value of $Q(-10)$ by plugging -10 into the formula for $Q(x)$. $Q(x)=5x^{2}-1$ $Q(-10)=5(-10^{2})-1=5\times(-10\times-10)-1=5\times100-1=500-1=499$
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