Answer
$a_{1}=2(1)+1=3$
$a_{2}=2(2)+1=5$
$a_{3}=2(3)+1=7$
$a_{4}=2(4)+1=9$
$a_{10}=2(10)+1=21$
$a_{15}=2(15)+1=31$
Work Step by Step
If we want to find a term, we have to substitute $n$ by its index:
$a_{1}=2(1)+1=3$
$a_{2}=2(2)+1=5$
$a_{3}=2(3)+1=7$
$a_{4}=2(4)+1=9$
$a_{10}=2(10)+1=21$
$a_{15}=2(15)+1=31$