Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set - Page 894: 23

$a_{1}=3(1)-1=2$ $a_{2}=3(2)-1=5$ $a_{3}=3(3)-1=8$ $a_{4}=3(4)-1=11$ $a_{10}=3(10)-1=29$ $a_{15}=3(15)-1=44$

If we want to find a term, we have to substitute $n$ by its index: $a_{1}=3(1)-1=2$ $a_{2}=3(2)-1=5$ $a_{3}=3(3)-1=8$ $a_{4}=3(4)-1=11$ $a_{10}=3(10)-1=29$ $a_{15}=3(15)-1=44$