Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 13 - Conic Sections - Mid-Chapter Review - Mixed Review - Page 873: 6

Answer

Parabola.

Work Step by Step

$y={{x}^{2}}-5$ It is written as: $\begin{align} & {{x}^{2}}=y+5 \\ & {{\left( x-0 \right)}^{2}}=4\left( \frac{1}{4} \right)\left( y+5 \right) \end{align}$ Compare the above equation with the standard form of a parabola ${{\left( x-h \right)}^{2}}=4a\left( y-k \right)$. Thus, it is a parabola equation. The graph of the parabola $y={{x}^{2}}-5$ is given below:
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