Answer
Center of circle is $\left( 4,-3 \right)$ and radius is $r=\sqrt{10}$.
Work Step by Step
Standard equation of the circle is:
${{\left( x-h \right)}^{2}}+{{\left( y-k \right)}^{2}}={{r}^{2}}$ (equation - 1)
And equation of the circle is ${{\left( x-4 \right)}^{2}}+{{\left( y+3 \right)}^{2}}=10$ (equation- 2)
Now compare both the equations.
$\begin{align}
& {{\left( x-4 \right)}^{2}}+{{\left( y+3 \right)}^{2}}=10 \\
& {{\left( x-\left( 4 \right) \right)}^{2}}+{{\left( y-\left( -3 \right) \right)}^{2}}=\sqrt{10} \\
\end{align}$
Center coordinate of circle is $\left( h=4,k=-3 \right)$.
And radius of circle is $r=\sqrt{10}$.
To graph, we plot the points $\left( 4,0.2 \right)$, $\left( 4,-6.2 \right)$, $\left( 0.85,-3 \right)$, and $\left( 7.2,-3 \right)$ which are, respectively, $\sqrt{10}$ units above, below, left and right of $\left( 4,-3 \right)$.
