Answer
$x=2{{y}^{2}}$
Work Step by Step
$x=2{{y}^{2}}$ (equation -1)
$\begin{align}
& y=-\frac{b}{2a} \\
& =-\frac{\left( 0 \right)}{2\cdot \left( 1 \right)} \\
& =0
\end{align}$
Now for the x value put $y=0$ in equation (1),
$\begin{align}
& x=-{{\left( 0 \right)}^{2}} \\
& =0
\end{align}$
The vertex is $\left( 0,0 \right)$.
Now choose some value of x on both sides of the vertex and compute the corresponding y value.
$\begin{matrix}
x & y \\
0 & 0 \\
2 & 1 \\
2 & -1 \\
8 & 2 \\
8 & -2 \\
\end{matrix}$
