Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 13 - Conic Sections - 13.1 Conic Sections: Parabolas and Circles - 13.1 Exercise Set - Page 854: 24

Answer

The graph for the equation $x={{y}^{2}}+3y$.

Work Step by Step

$x={{y}^{2}}+3y$ (equation -1) $\begin{align} & y=-\frac{b}{2a} \\ & =-\frac{\left( 3 \right)}{2\cdot \left( 1 \right)} \\ & =-\frac{3}{2} \end{align}$ Now for the x value put $y=-\frac{3}{2}$ in equation (1), $\begin{align} & x=-{{\left( -\frac{3}{2} \right)}^{2}}+3\cdot \left( -\frac{3}{2} \right) \\ & =\frac{9}{4}-\frac{9}{2} \\ & =\frac{9-18}{4} \\ & =-\frac{9}{4} \end{align}$ The vertex is$\left( -\frac{9}{4},-\frac{3}{2} \right)$. Now choose some value of x on both sides of the vertex and compute the corresponding y value. $\begin{matrix} x & y \\ 0 & 0 \\ 4 & 1 \\ -2 & -1 \\ -2 & -2 \\ \end{matrix}$
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