Answer
$x^2+y^2=64$
Work Step by Step
Using $(x-h)^2+(y-k)^2=r^2$ or the Center-Radius form of the equation of circles, the equation of the circle with center, $(
0,0
),$ and radius, $r=
8
,$ is
\begin{array}{l}\require{cancel}
(x-0)^2+(y-0)^2=8^2
\\\\
x^2+y^2=64
.\end{array}