Answer
The solution set is $\left\{-1, 0, 1\right\}$.
Work Step by Step
Factor our $x$ to obtain:
$x(x^2-1)=0$
RECALL:
A difference of two squares can be factored using the formula:
$a^2-b^2=(a-b)(a+b)$
Factor the difference of two squares to obtain:
$x(x-1)(x+1)=0$
Equate each factor to 0, and then solve each equation to obtain:
$x=0 \text{ or } x-1=0 \text{ or } x+1 = 0
\\x=0 \text{ or } x=1 \text{ or } x=-1$
The solution set is $\left\{-1, 0, 1\right\}$.
