Answer
$x$
Work Step by Step
Using the laws of exponents, the given expression, $
\left( \dfrac{x^{2}}{x^{3}} \right)^{-1}
,$ simplifies to
\begin{array}{l}\require{cancel}
\left( x^{2-3} \right)^{-1}
\\\\=
\left( x^{-1} \right)^{-1}
\\\\=
x^{-1(-1)}
\\\\=
x^{1}
\\\\=
x
.\end{array}
