Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6 - Page 224: 70

$\dfrac{x^4}{16}$

Using the laws of exponents, the given expression, $ (4x^{-2})^{-2} ,$ is equivalent to \begin{array}{l}\require{cancel} 4^{-2}x^{-2(-2)} \\\\= 4^{-2}x^{4} \\\\= \dfrac{x^4}{4^2} \\\\= \dfrac{x^4}{16} .\end{array}