Answer
$\dfrac{8}{n^{6}}$
Work Step by Step
Using the laws of exponents and the rule $(a^{m})^{n}=a^{mn}$, the given expression, $ (2n^{-2})^{3} ,$ is equivalent to \begin{array}{l}\require{cancel} 2^3n^{-2(3)} \\\\= 8n^{-6} \\\\=
\dfrac{8}{n^{6}}
.\end{array}
For more complicated problems, it is helpful to remember that you can flip the location of numbers with negative exponents. In other words, you can move numbers with a negative exponent that are in the numerator to the denominator, and you can move numbers with a negative exponent in the denominator to the numerator.
