Answer
$\dfrac{1}{32}$
Work Step by Step
Using the laws of exponents, the given expression, $
2^{-7}\cdot2^{2}
,$ is equivalent to
\begin{array}{l}\require{cancel}
2^{-7+2}
\\\\=
2^{-5}
\\\\=
\dfrac{1}{2^5}
\\\\=
\dfrac{1}{32}
.\end{array}
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6 - Page 223: 22
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