Answer
$45-28i$
Work Step by Step
We multiply each term of the first complex number with the second complex number and simplify:
$(7-2i)^{2}$
=$(7-2i)(7-2i)$
=$7(7-2i)-2i(7-2i)$
=$49-14i-14i+4i^{2}$
=$49-28i+4(-1)$ [We substitute -1 in place of $i^{2}$ as $i^{2}=-1$]
=$49-4-28i$
=$45-28i$
