Answer
$-21-12i$
Work Step by Step
We multiply each term of the first complex number with the second complex number and then simplify:
$(-2-3i)(6-3i)$
=$-2(6-3i)-3i(6-3i)$
=$-12+6i-18i+9i^{2}$
=$-12-12i+9(-1)$ [We substitute -1 in place of $i^{2}$ as $i^{2}=-1$]
=$-12-9-12i$
=$-21-12i$
