Answer
$-2+23i$
Work Step by Step
We multiply each term of the first complex number with the second complex number and then simplify:
$(2+3i)(5+4i)$
=$2(5+4i)+3i(5+4i)$
=$10+8i+15i+12i^{2}$
=$10+23i+12i^{2}$
=$10+23i+12(-1)$ [as $i^{2}=-1$]
=$10-12+23i$
=$-2+23i$
