Answer
$-11-5i$
Work Step by Step
We multiply each term of the first complex number with the second complex number and then simplify:
$(-3-8i)(1-i)$
=$-3(1-i)-8i(1-i)$
=$-3+3i-8i+8i^{2}$
=$-3-5i+8(-1)$ [We substitute -1 in place of $i^{2}$ as $i^{2}=-1$]
=$-3-8-5i$
=$-11-5i$