Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - Chapter Review - Page 534: 8

Answer

$10\sqrt{3}$

Work Step by Step

The given expression is $=\sqrt{6}(\sqrt{18}+\sqrt{8})$ Factor as square terms. $=\sqrt{3\cdot 2}(\sqrt{9\cdot 2}+\sqrt{4\cdot 2})$ Use product property of square roots. $=\sqrt{3}\cdot \sqrt{2}(\sqrt{9}\cdot \sqrt{2}+\sqrt{4}\cdot \sqrt{2})$ Simplify. $=\sqrt{3}\cdot \sqrt{2}(3\sqrt{2}+2\sqrt{2})$ Factor out $2$. $=\sqrt{3}\cdot \sqrt{2}\sqrt{2}(3+2)$ Use product property of square roots. $=\sqrt{3}\cdot \sqrt{2^2}(3+2)$ Simplify. $=\sqrt{3}\cdot2(5)$ $=10\sqrt{3}$
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