Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - Chapter Review - Page 534: 6

Answer

$9\sqrt[3]2$

Work Step by Step

The given expression is $=15\sqrt[3]2-2\sqrt[3]{54}$ Factor as cube terms. $=15\sqrt[3]2-2\sqrt[3]{27\cdot 2}$ Use product property of cube roots. $=15\sqrt[3]2-2\sqrt[3]{27}\cdot \sqrt[3]{2}$ Simplify. $=15\sqrt[3]2-2\cdot 3\sqrt[3]{2}$ $=15\sqrt[3]2-6\sqrt[3]{2}$ Factor out $\sqrt[3]{2}$. $=(15-6)\sqrt[3]2$ Simplify. $=9\sqrt[3]2$
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