Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - Chapter Review - Page 534: 2

Answer

$\frac{3 \sqrt{35y}}{7y}$

Work Step by Step

The given expression is $=\sqrt{\frac{45}{7y}}$ Use quotient property of square roots. $=\frac{\sqrt{45}}{\sqrt{7y}}$ Factor as square terms. $=\frac{\sqrt{9\cdot 5}}{\sqrt{7y}}$ Use product property of square roots. $=\frac{\sqrt{9}\cdot \sqrt{5}}{\sqrt{7y}}$ Simplify. $=\frac{3 \sqrt{5}}{\sqrt{7y}}$ Multiply by $\frac{\sqrt{7y}}{\sqrt{7y}}$. $=\frac{3 \sqrt{5}}{\sqrt{7y}}\cdot \frac{\sqrt{7y}}{\sqrt{7y}}$ Use product property of square roots. $=\frac{3 \sqrt{5\cdot 7y}}{\sqrt{(7y)^2}}$ Simplify. $=\frac{3 \sqrt{35y}}{7y}$
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