Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.4 - Solving Quadratic Equations by Completing the Square - Exercises - Page 512: 49

Answer

No

Work Step by Step

$$y=\frac14(x+2)^2-4$$ Here the graph of this function will open up as $a>0$ and it has a minimum value. Also it has vertex at $(-2,-4)$ that is in the third quadrant. So the given graph could not represent the function because its vertex is in the fourth quadrant.
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