Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1-9.3 - Quiz - Page 504: 12

Answer

$30\sqrt{2}$

Work Step by Step

The given expression is $=\sqrt{6}(7\sqrt{12}-4\sqrt{3})$ Factor as square terms. $=\sqrt{6}(7\sqrt{4\cdot 3}-4\sqrt{3})$ Use product property of square roots. $=\sqrt{6}(7\sqrt{4}\cdot \sqrt{3}-4\sqrt{3})$ Simplify. $=\sqrt{6}(7(2) \sqrt{3}-4\sqrt{3})$ Use distributive property. $=\sqrt{6}\sqrt{3}(14 -4)$ Simplify. $=\sqrt{6}\sqrt{3}(10)$ Use product property of square roots. $=10\sqrt{6\cdot 3}$ Factor as square terms. $=10\sqrt{9\cdot 2}$ Use product property of square roots. $=10\sqrt{9}\cdot \sqrt{2}$ Simplify. $=10(3)\sqrt{2}$ $=30\sqrt{2}$
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