Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1-9.3 - Quiz - Page 504: 10

Answer

$-4\sqrt{5}+7\sqrt{10}$

Work Step by Step

The given expression is $=2\sqrt{5}+7\sqrt{10}-3\sqrt{20}$ Factor as square terms. $=2\sqrt{5}+7\sqrt{10}-3\sqrt{4\cdot 5}$ Use product property of square roots. $=2\sqrt{5}+7\sqrt{10}-3\sqrt{4}\cdot \sqrt{5}$ Simplify. $=2\sqrt{5}+7\sqrt{10}-3(2)\sqrt{5}$ $=2\sqrt{5}+7\sqrt{10}-6\sqrt{5}$ $=2\sqrt{5}-6\sqrt{5}+7\sqrt{10}$ Use distributive property. $=(2-6)\sqrt{5}+7\sqrt{10}$ Simplify. $=-4\sqrt{5}+7\sqrt{10}$
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