Answer
Graph $C$
Work Step by Step
The function in the form $y=a(x-h)^2+k$ has a vertex at $(h,k)$.
Given: $$y=-(x+1)^2-3.$$ Rewrite as:
$$y=-(x-(-1))^2+(-3)$$
If follows that $a=-1$, $h=-1$, $k=-3$. The vertex is $$(h,k)=(-1,-3)$$ and the parabola opens down since $a<0$.
The graph which fits is graph $C$.
