Chapter 8 - Graphing Quadratic Functions - 8.4 - Graphing f(x) = a(x-h)^2 + k - Exercises - Page 447: 34

Vertex: $(6,-5)$. Axis of symmetry: $x=6$

The quadratic function in the form $y=a(x-h)^2+k$ has the vertex $(h,k)$ and the axis of symmetry $x=h$. Given: $$y=-(x-6)^2-5.$$ Therefore $h=6$, $k=-5$. The vertex is: $$(h,k)=(6,-5).$$ The axis of symmetry is: $$x=6.$$