Answer
$(w-3)(w-1)$.
Work Step by Step
The given polynomial is
$=w^2-4w+3$
Standard form is $x^2+bx+c$.
We have $b=-4$ and $c=3$.
$b$ is negative and $c$ is positive.
Factor pair of $3$, whose sum is $-4$:
$-3,-1$
The values of $p$ and $q$ are $-3$ and $-1$.
Hence, the factor of the polynomial is $(w+p)(w+q)=(w-3)(w-1)$.
Check:-
$=(w-3)(w-1)$
$=w^2-w-3w+3$
$=w^2-4w+3$
True.
