Answer
$(x-2)(x-12)$.
Work Step by Step
The given polynomial is
$=x^2-14x+24$
Standard form is $x^2+bx+c$.
We have $b=-14$ and $c=24$.
$b$ is negative and $c$ is positive.
Factor pair of $24$, whose sum is $-14$:
$-2,-12$
The values of $p$ and $q$ are $-2$ and $-12$.
Hence, the factor of the polynomial is $(x+p)(x+q)=(x-2)(x-12)$.
Check:-
$=(x-2)(x-12)$
$=x^2-12x-2x+24$
$=x^2-14x+24$
True.
