Answer
$(x+8)(x+1)$.
Work Step by Step
The given polynomial is
$=x^2+9x+8$
Standard form is $x^2+bx+c$.
We have $b=9$ and $c=8$.
The value of $c$ is positive.
Factor pair of $8$, whose sum is $9$:
$8,1$
The values of $p$ and $q$ are $8$ and $1$.
Hence, the factor of the polynomial is $(x+p)(x+q)=(x+8)(x+1)$.
Check:-
$=(x+8)(x+1)$
$=x^2+x+8x+8$
$=x^2+9x+8$
True.
