Answer
$(n-5)(n-7)$.
Work Step by Step
The given polynomial is
$=n^2-12n+35$
Standard form is $x^2+bx+c$.
We have $b=-12$ and $c=35$.
$b$ is negative and $c$ is positive.
Factor pair of $35$, whose sum is $-12$:
$-5,-7$
The values of $p$ and $q$ are $-5$ and $-7$.
Hence, the factor of the polynomial is $(n+p)(n+q)=(n-5)(n-7)$.
Check:-
$=(n-5)(n-7)$
$=n^2-7n-5n+35$
$=n^2-12n+35$
True.
