Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - 5.4 - Solving Special Systems of Linear Equations - Exercises - Page 258: 35

Answer

The solutions are $x=1$ and $x=5$.

Work Step by Step

The given equation is $\Rightarrow |x-7|=|2x-8|$ Write related linear equations. $\Rightarrow x-7=2x-8$ or $x-7=-(2x-8)$ Solve the first equation. $\Rightarrow x-7=2x-8$ Add $8-x$ to each side. $\Rightarrow x-7+8-x=2x-8+8-x$ Simplify. $\Rightarrow 1=x$ Solve the second equation. $\Rightarrow x-7=-(2x-8)$ Use distributive property. $\Rightarrow x-7=-2x+8$ Add $-8-x$ to each side. $\Rightarrow x-7-8-x=-2x+8-8-x$ Simplify. $\Rightarrow -15=-3x$ Divide each side by $-3$. $\Rightarrow \frac{-15}{-3}=\frac{-3x}{-3}$ Simplify. $\Rightarrow 5=x$ Check $x=1$ $\Rightarrow |x-7|=|2x-8|$ $\Rightarrow |1-7|=|2(1)-8|$ $\Rightarrow |-6|=|2-8|$ $\Rightarrow |-6|=|-6|$ $\Rightarrow 6=6$ True. Check $x=5$ $\Rightarrow |x-7|=|2x-8|$ $\Rightarrow |5-7|=|2(5)-8|$ $\Rightarrow |-2|=|10-8|$ $\Rightarrow |-2|=|2|$ $\Rightarrow 2=2$ True. Hence, the solutions are $x=1$ and $x=5$.
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